**Polaris Software**is a world renowned banking and insurance software company founded in 1993. The main function of the company is that it offers comprehensive solutions for corporate banking, wealth & asset management and insurance. The

**Polaris-Test-Pattern**and

**Selection Procedure**is as follows:

Selection Process:

The company conducts recruitment process every year to
select new candidates. The selection process of the company consists of 4
rounds. These rounds are as follows:

- Written
Exam
- Group
Discussion
- Technical
Interview
- HR
Interview

Academic Criteria:

- The
candidates must not have a gap year.
- The
candidate must not have any active backlogs at the time of campus
recruitment.
- The
candidate must have secured an aggregate of 60% in 10th , 12th and B.Tech.

Pattern of Written Exam:

**Testing Areas**

**Number of Questions**

Aptitude 30

Technical 40

**Total**

**70**

The total time allotted to the written exam is 60 minutes.
There is

**no negative marking**in the paper.**Aptitude**section consists of questions based on data interpretation, graphs, blood relations, statement reasoning, etc. Also, there are questions from basic mathematics like time, speed & distance, algebra, arithmetic, permutation & combination, etc. Further, there are questions from English language like grammar usage, fill in the blanks, etc.**Technical**section involved questions from core subjects like**C & C++ programming, DBMS, OS, Networking**. Also, there are questions from electronics subjects. This section was tough and required thorough preparation. A person whose basics are clear could easily excel in this section.

Overall the level of the paper is

**moderate to difficult**. Only those candidates who clear the written exam will qualify for the next round.__Written test Model Questions:__

**POLARIS Technical Questions**

**Choose the correct statement**

- Processes
may be either independent or cooperating processes
- Thread
Control block is a container which holds every information related to a
process
- Deadlock
prevention is not possible, avoidance is possible to some extent
- Cascading
termination refers to the concept of killing the child processes though a
parent process also exists

**Answer:**A

**'using' in C++ is for**

- 'using'
does not exist in C++
- used
for library functions
- 'using'
is a literal in C++
- used
for pointers

**Answer:**B

Note : it is also used often for namespaces.

**If a page number is not found in the TLB, then it is known as a ___________**

- TLB
miss
- Buffer
miss
- TLB
hit
- TLB
not found

**Answer:**A

**FDM is applied when:**

- The bandwidth
of the link( in hertz) is greater than the combined bandwidth of the
signal to be transmitted.
- The
bandwidth of the link(in hertz) is equal to the combined bandwidth of the
signal to be transmitted.
- The
bandwidth of the link(in hertz) is lesser than the combined bandwidth of
the signal to be transmitted.
- The
bandwidth of the link(in hertz) is equal to the bandwidth of the signal
to be transmitted.

**Answer:**A

**Reference is _________**

- alias
of an object
- used
to rename an object
- a
special operator
- a
pointer to virtual function

**Answer:**A

**The size of a page is typically _________**

- Varied
- Power
of 2
- Power
of 4
- Power
of 8

**Answer:**B

__POLARIS SOFTWARE Aptitude Questions__

**DIRECTIONS for the question 1 to 5: Solve the following question and mark the best possible option.**

1. If x > y

2. If x ≥ y

3. If x < y

4. If x ≤ y

5. If x = y or the relationship between x and y cannot be established

**I. x**^{2}+ 12x + 36 = 0

II. y^{2}+ 15y + 56 = 0- 1
- 2
- 3
- 4
- 5

**Answer:**A

I. x

^{2}+ 12x + 36 = 0

Or, (x + 6)

^{2}= 0

Or, (x + 6) = 0

Or, x = - 6

II. y

^{2}+ 15y + 56 = 0

Or, y

^{2}+ 7y + 8y + 56 = 0

Or, y(y + 7) + 8(y + 7) = 0

Or, (y + 7) (y + 8) = 0

∴ y = - 7, - 8

∴ x > y

**I. x**^{2}= 35

II. y^{2}+ 13y + 42 = 0- 1
- 2
- 3
- 4

**Answer:**A

I. x2 = 35

∴ x = +- √35

II. y

^{2}+ 13y + 42 = 0

Or, y

^{2}+ 6y + 7y + 42 = 0

Or, y(y + 6) + 7 (y + 6) = 0

Or, (y + 6) (y + 7) = 0

∴ y = -6, - 7

∴ x > y

**I. 2x**^{2}– 3x – 35 = 0

II. y2 – 7y + 6 = 0- 1
- 2
- 3
- 4
- 5

**Answer:**E

I. 2x

^{2}– 3x – 35 = 0

Or, 2x

^{2}– 10x + 7x – 35 = 0

Or, 2x(x – 5) + 7 (x – 5) = 0

Or, (2x + 7) (x – 5) = 0

∴ x = - 7/2 , 5

II. y

^{2}– 7y + 6 = 0

Or, y

^{2}– y – 6y + 6 = 0

Or, y(y – 1) -6 (y – 1)

Or, (y – 1) (y – 6) = 0

∴ y = 1, 6

No relation can be established between x and y.

**I. 6x**^{2}– 29x + 35 = 0

II. 2y^{2}- 19y + 35 = 0- 1
- 2
- 3
- 4
- 5

**Answer:**D

I. 6x

^{2}– 29x + 35 = 0

Or. 6x

^{2}– 15x – 14x + 35 = 0

Or, 3x(2x – 5) -7(2x – 5) = 0

Or, (3x – 7) (2x – 5) = 0

∴ x = - 7/2 , -5/2

II. 2y

^{2}– 19y + 35 = 0

Or, 2y

^{2}– 14y – 5y + 35 = 0

Or, 2y(y – 7) – 5(y – 7) = 0

Or, (2y – 5) (y – 7) = 0

∴ y = 5/2 , 7

∴ x <= y

**I. 12x**^{2}– 47x + 40 = 0

II. 4y^{2}+ 3y – 10 = 0- 1
- 2
- 3
- 4
- 5

**Answer:**B

I. 12x

^{2}– 47x + 40 = 0

Or, 12x

^{2}– 32x – 15x + 40 = 0

Or, 4x(3x – 8) -5(3x – 8) = 0

Or, (4x – 5) (3x – 8) = 0

∴ x = 5/4 , 8/3

II. 4y

^{2}+ 3y – 10 = 0

Or, 4y

^{2}+ 8y – 5y – 10 = 0

Or, 4y(y + 2) -5(y + 2) = 0

Or, (4y - 5) (y + 2) = 0

∴ x = 5/4 , -2

∴ x >= y

**DIRECTIONS for the question 6 to 10:**Solve the following question approximately and mark the best possible answer. You are not expected to find the exact value.

**39% of 129 - 43% of 97 = ?**- 14
- 15
- 17
- 9

**Answer:**D

129×39/100 = 50.3

97×43/100 = 41.7

? = 50.3-41.7 ≈ 9

**84.99 × 18.98 ÷ 7.2 + 62.7 = ?**- 390
- 340
- 287
- 240

**Answer:**C

? = 85×19 ÷ 7.2 + 62.7

= 85 × 2.64 + 62.7

= 224.3 + 62.7 = 287

**Find the value of Square root of ( √36.1 + √28.9 ).**- 3.4
- 4.2
- 4.5
- 2.8

**Answer:**A

√36.1 = 6

√28.9 = 5.4

6 + 5.4 = 11.4

√11.4 = 3.4

**56.5% of 286 + 45.8% of 435 = ?**- 85
- 75
- 361
- 125

**Answer:**C

286 × 56.5/100 = 161.6

435 × 45.8/100 = 199.2

? = 161.6 + 199.2 ≈ 361

**9.71 × 52.8 ÷ 50.8 + 83.4 = ?**- 93.58
- 103.1
- 53.7
- 108.4

**Answer:**A

? = 9.71 × 52.8 ÷ 50.8 + 83.4

= 10.1 + 83.4 = 93.5

## 2 comments:

This could also help you to pass an interview to college!

Hello, I would like to thank you for sharing this interesting information. I'm sure it will be definitely useful for young programmers. Personally I will use it in my 100 yen sushi house sample task.

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